The area of a playground is 64 square yards. The length of the playground is 4 times longer than its width. How can I solve this?

Answer:If you are looking for the dimensions of the playground, they are that the width is 4 yards and the length is 16 yardsStep-by-step explanation:We need to know 2 things here:  first, the area of a rectangle which is A = l×w,and then we need to know how to express one dimension in terms of the other, since we have way too many unknowns right now to solve for anything!We are told that the length is 4 times the width, so if the width is "w", then the length is "4w".  We know the area is 64, so let's sub in those values where they belong in the area formula:64 = 4w(w).  Multiplying to simplify we get[tex]64=4w^2[/tex]The easiest way to do this is to divide both sides by 4 to get [tex]16=w^2[/tex]and when you take the square root of 16 you get 4 and -4.  However, the two things in math that will never ever be negative are distance measurements and time.  So the -4 won't do.  That means that w = 4.  If that be the case, and the length is 4 times the width, then the length is 16.  And there you go!